-v var=<path> on windows

Hi all,

I'm running the gnuwin32 port of gawk 3.1.3 on win2k.

Im trying to pass a path to a gawk variable

I know that I need to escape the backslashes like

gawk -v var="c:\\path\\including blanks\\to\\file" ...

My problem now is that the path I want to pass to gawk comes from a
batch file parameter

gawk -v var="%1"

As expected gawk issues "warning: escape sequence '\x' treated as
plain 'x'" if %1 contains a backslash.


Does anyone know a way around this?


TIA Lorenz

On Thu, 12 May 2005 10:25:34 +0200, Lorenz Lenhardt <lorenz@famlen.de>
wrote:

>Hi all,
>
>I'm running the gnuwin32 port of gawk 3.1.3 on win2k.
>
>Im trying to pass a path to a gawk variable
>
>I know that I need to escape the backslashes like
>
>	gawk -v var="c:\\path\\including blanks\\to\\file" ...
>
>My problem now is that the path I want to pass to gawk comes from a
>batch file parameter
>
>	gawk -v var="%1"
>
>As expected gawk issues "warning: escape sequence '\x' treated as
>plain 'x'" if %1 contains a backslash.
>
>
>Does anyone know a way around this?
>
awk "BEGIN{var=ARGV[1]; ARGV[1]=\"\"; ARGC--;print var}" %1

all one line - with or without "" around the string.  Of course, in a
real-world program, sanity checking would be needed and also perhaps
more sophisticated ARGV/ARGC handling


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"Lorenz Lenhardt" <lorenz@famlen.de> wrote in message
 news:6046819ss5asp8ksf5mvmb0iu78tnstf7r@
4ax.com...
> Hi all,
>
> I'm running the gnuwin32 port of gawk 3.1.3 on win2k.
>
> Im trying to pass a path to a gawk variable
>
> I know that I need to escape the backslashes like
>
> gawk -v var="c:\\path\\including blanks\\to\\file" ...
>
> My problem now is that the path I want to pass to gawk comes from a
> batch file parameter
>
> gawk -v var="%1"
>
> As expected gawk issues "warning: escape sequence '\x' treated as
> plain 'x'" if %1 contains a backslash.
>
>
> Does anyone know a way around this?
>
>
> TIA Lorenz

one way:
set VAR1=%1
gawk -v vv="VAR1" .... var=ENVIRON[vv]; ...

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