return each elemet from one input line with a newline

hi all,

is there a way to create an awk script that can handle the follwing task:

i got one line (it's my unix/windows PATH variable) that has a delimiter
(":") between each element:

/cygdrive/d/program files/app1:/usr/bin:/sth/else:

what i need to have now is a script that returns me the following

/cygdrive/d/program files/app1
/usr/bin
/sth/else

so that each element is printed in a seperat row. but mention that there
might be blanks ("/cygdrive/d/program files/app1")
within my elements..

thanks in advance

cheers
joerg

Le Thu, 28 Apr 2005 19:05:07 +0200, joerg mauz a écrit_:

> hi all,
>
> is there a way to create an awk script that can handle the follwing task:
>
> i got one line (it's my unix/windows PATH variable) that has a delimiter
> (":") between each element:
>
> /cygdrive/d/program files/app1:/usr/bin:/sth/else:
>
> what i need to have now is a script that returns me the following
>
> /cygdrive/d/program files/app1
> /usr/bin
> /sth/else
>
> so that each element is printed in a seperat row. but mention that there
> might be blanks ("/cygdrive/d/program files/app1")
> within my elements..
>
> thanks in advance
>
> cheers
>     joerg

Just use RS properly :

$ echo "/cygdrive/d/program files/app1:/usr/bin:/sth/else:" | awk
'{print}' RS=":" /cygdrive/d/program files/app1
/usr/bin
/sth/else


$ echo "/cygdrive/d/program files/app1:/usr/bin:/sth/else:" | awk '1' RS=":"
/cygdrive/d/program files/app1
/usr/bin
/sth/else

it works !

thanks very much !!!