Re: Passing string to awk

warezcrc@hotmail.com wrote:
> make it look like this ex.
>
> ls -Fl |  awk '{print "\t"$3, $4, "'"$PWD"'/"$9}' | sed 1d
>
> and you get what you want i believe, had the same problem  what you are
> looking for in this ex. is this part '"$PWD"' that will get you your
> variable, replace $PWD with yours.
>

I didn't see the original posting for this response, but that's the
worst possible way to use shell variables with awk (read the
comp.lang.awk and comp.unix.shell FAQs), and you don't need the sed.

Do this:

ls -Fl |awk -vpwd="$PWD" 'NR>1{printf "\t%s %s %s/%s\n",$3,$4,pwd,$9}'

If your awk doesn't support -v, use the ENVIRON array or set the
variable at the end of the line (again see the FAQs).

Ed.

In article <n5-dncs_aujYRl_cRVn-rA@comcast.com>,
Ed Morton  <morton@lsupcaemnt.com> wrote:
>Do this:
>
>ls -Fl |awk -vpwd="$PWD" 'NR>1{printf "\t%s %s %s/%s\n",$3,$4,pwd,$9}'
>
>If your awk doesn't support -v, use the ENVIRON array or set the
>variable at the end of the line (again see the FAQs).

Any awk that doesn't support -v won't have ENVIRON in it
either.  In which case, you can use

ls -Fl | gawk '.....' pwd=$PWD -

Arnold
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