Convert Columns to Rows

I have a very large csv file from a spreadsheet.  The first 2 columns are a
description, and the next 52 columns are a value for a w of the year
(using only 3 ws in this example)

Is there a way in Awk to transform these into a format that is loadable into
a relational database such as Oracle?

For example, I'd like to change the following into the latter format.  The
first column would be a derived w number.  That first column is something
I could live without if I had to.

Any help with a simple awk would be appreciated.



washer,sunday,33,44,55
dryer,monday,667,333,44
refrig,monday,555,876,99



1    washer sunday 33
2    washer sunday 44
3    washer sunday 55
1    dryer monday 667
2    dryer monday 333
3    dryer monday 444
1    refrig monday 555
2    refrig monday 876
3    refrig monday 99

In article <bebs62-3ff.ln1@turf.turgidson.com>,
Buck Turgidson <jc_va@hotmail.com> wrote:
...
Convert:
>washer,sunday,33,44,55
>dryer,monday,667,333,44
>refrig,monday,555,876,99

To:

>1    washer sunday 33
>2    washer sunday 44
>3    washer sunday 55
>1    dryer monday 667
>2    dryer monday 333
>3    dryer monday 444
>1    refrig monday 555
>2    refrig monday 876
>3    refrig monday 99

BEGIN {FS=","}
{
for (i=3; i<=NF; i++)
print i-2,$1,$2,$i
}

Buck Turgidson wrote:
> I have a very large csv file from a spreadsheet.  The first 2 columns are 
a
> description, and the next 52 columns are a value for a w of the year
> (using only 3 ws in this example)
>
> Is there a way in Awk to transform these into a format that is loadable in
to
> a relational database such as Oracle?

Sure:

gawk -F, '{for (i=3;i<=NF;i++) print i-2, $1, $2, $i}'

Ed.

>
> BEGIN {FS=","}
> {
> for (i=3; i<=NF; i++)
>     print i-2,$1,$2,$i
> }
>

Just beautiful.....Thanks to both.