include_once() - always included?

Hi All,

Always looking for efficiency, consider the following code:

<?php
function one($arg){
if ($arg == 1){
include_once(...);
do some stuff...
}else{
do some stuff...
}
}
?>

If the above function is called with an argument value of '2', is the
'include_once' file included?

Regards,
Aaron

On Fri, 15 Oct 2004 17:58:33 -0500, "Aaron DeLoach" <aaron@deloachcorp.com>
wrote:

>Always looking for efficiency, consider the following code:
>
><?php
>function one($arg){
>    if ($arg == 1){
>        include_once(...);
>        do some stuff...
>    }else{
>        do some stuff...
>    }
>}
>?>
>
>If the above function is called with an argument value of '2', is the
>'include_once' file included?

No. (What happened when you tried it?)

--
Andy Hassall / <andy@andyh.co.uk> / <http://www.andyh.co.uk>
<http://www.andyhsoftware.co.uk/space> Space: disk usage analysis tool

ehrm no... please tell me this is a joke :P

Aaron DeLoach wrote:
> Hi All,
>
> Always looking for efficiency, consider the following code:
>
> <?php
> function one($arg){
>     if ($arg == 1){
>         include_once(...);
>         do some stuff...
>     }else{
>         do some stuff...
>     }
> }
> ?>
>
> If the above function is called with an argument value of '2', is the
> 'include_once' file included?
>
> Regards,
> Aaron
>
>
>
>