newbie question:extract last argument in a line when number of arguments is unknown

Hi,

I need to extract the last argument of a given line, when number of
arguments in line is unkown.

Is there a way for doing it in a single awk command?
How can it be done generally? (without the one command limitation)

Any help would be appreciated,

thanks,
yaniv

In article <d742ebad.0402240203.46836e43@posting.google.com>,
yaniv <valiky@hotmail.com> wrote:

% I need to extract the last argument of a given line, when number of
% arguments in line is unkown.

You might want to give an example of what you hope to achieve. Given
this:

awk -f somefile.awk here are some arguments

there's a variable called ARGC which will be set to 5 and an array
called ARGV. ARGV[1] will be set to "here", ..., ARGV[4] will be
set to "arguments". ARGV[4] is the same as ARGV[ARGC-1].

On some systems, this will not work. The reason is that awk on those systems
s the original, pre-1987 awk, while the language discussed in this group
is invoked using the name nawk. The only widely used system with this
characteristic is Solaris, and you can fix it by setting the path
appropriately (to start with /usr/xpg4/bin).

--

Patrick TJ McPhee
East York  Canada
ptjm@interlog.com