print problem? (CGI)

The following code doesn't run.. I don't know what's wrong with it, can some
one help me?

print << START_HERE;
<p>Thanks a thousand times... ^_^ </p>
START_HERE

thx...

In article <UKSmb.59582$3f.36505@twister01.bloor.is.net.cable.rogers.com>, Ben Wan wrote:[c
olor=darkred]
>The following code doesn't run.. I don't know what's wrong with it, can som
eone help me?
>
>print << START_HERE;
><p>Thanks a thousand times... ^_^ </p>
>START_HERE[/color]

print << 'START_HERE';

You need to quote the bareword identifier for the end of the "here" block.
Note that if you want  variable substitution, you should use "START_HERE"
instead.  (Double-quotes to indicate interpolation.)

--
Vorxion - Member of The Vortexa Elite

sorry, but can you tell me what is variable substitution? and does it do any
thing on "START_HERE"?
Thx...

"Vorxion" <vorxion@fairlite.com> ¼¶¼g©ó¶l¥ó·s»D:3f9c0236$1_1@news.iglou.com...
> In article <UKSmb.59582$3f.36505@twister01.bloor.is.net.cable.rogers.com>,
 Ben Wan wrote: 
>
> print << 'START_HERE';
>
> You need to quote the bareword identifier for the end of the "here" block.
> Note that if you want  variable substitution, you should use "START_HERE"
> instead.  (Double-quotes to indicate interpolation.)
>
> --
> Vorxion - Member of The Vortexa Elite

In article <axUmb.16068$7B1.9748@news04.bloor.is.net.cable.rogers.com>, Ben Wan wrote:[colo
r=darkred]
>sorry, but can you tell me what is variable substitution? and does it do an
ything on "START_HERE"?
>Thx...[/color]

First, don't top-post.  It's annoying and confusing.

And to answer your question, if you do:

print << 'END_HERE';
Some $nice text.
END_HERE

It will print:
Some $nice text.

If you do:

$nice = 'substituted';
print << "END_HERE";
Some $nice text.
END_HERE

It will print:
Some substituted text.

Get the idea?  Look up the difference between interpolated and
non-interpolated quoting mechanisms.  Apply it to 'here' blocks.

--
Vorxion - Member of The Vortexa Elite