Mathematica - sorry for the previous massage

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Author

sorry for the previous massage

omur.tosun@gmail.com

2007-04-21, 10:12 pm

a = Lambda[d]/(Lambda[d] + Lambda[in]);

> P(0, 0) = 1/(k + (Lambda[in] / Mu[in]) * (k - 1) +
(Lambda[in] / Mu[m]) * (k - 1) +
a* ((1 - a^(n - k)) / (1 - a)) +
(Lambda[in] / Mu[in])* a * ((1 - a^(n -k)) / (1 - a)) +
(Lambda[in] / Mu[M]) * a * (( 1 - a^(n -k)) / (1 - a)) +
(Lambda[d] / Mu[D]) * a^(n - k));
>
Availability (A) = P(0,0)*(k + (a * (1-a^(n-k))))

x=(dA/dLambda(in))--->it gives error massages like using inverse function

i use P() only for writing here. after i take x=(dA/dLambda(in)) i want to find the value using solve[x==0,Lambda(in)] but again i couldn't get any solution..i don't understand what if i do something wrong...

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