Home > Archive > Mathematica > October 2006 > compute limit
You are viewing an archived Text-only version of the thread.
To view this thread in it's original format and/or if you want to reply to
this thread please [click here]
|
|
| Frank Hechtner 2006-10-19, 4:21 am |
| Hi,
i?m in trouble with the calculation of limits. my expression is the
following
((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> ?
as you see, the limit is r when x approaches ?.
Unfortunately when using limit the output is
Limit[((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> ?].
I dont see whats going wrong. Does limit only compute numerical expression?
Thanks for your help
Frank
| |
|
| Dear Frank,
you have to tell Mathematica sth about your
variables, i.e. which is real, positive, ...;
otherwise Mathematica assumes them to be complex.
But for arbitrary complex numbers a closed solution
need not exist.
Try this
Limit[((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> \[Infinity],
Assumptions -> {r > 0, s > 0, s < 1}]
Bye
Ben
Frank Hechtner schrieb:
> Hi,
>
> i?m in trouble with the calculation of limits. my expression is the
> following
>
> ((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> ?
>
> as you see, the limit is r when x approaches ?.
>
> Unfortunately when using limit the output is
>
> Limit[((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> ?].
>
> I dont see whats going wrong. Does limit only compute numerical expression?
>
> Thanks for your help
>
> Frank
| |
|
| Hi Frank,
in your expression there are symbols not defined.
I'll try to define them in this attempt:
In[1]:=Assuming[{r>0,0<s<1},
Limit[((1 + r)^t*(1 - s) + s)^(1/t) - 1, t ->Infinity]]
Out[1]= r
HTH,
~Scout~
"Frank Hechtner" <frank.hechtner@rub.de>
news:eh79cr$dpb$1@smc.vnet.net...
> Hi,
>
> i?m in trouble with the calculation of limits. my expression is the
> following
>
> ((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> ?
>
> as you see, the limit is r when x approaches ?.
>
> Unfortunately when using limit the output is
>
> Limit[((1 + r)^t*(1 - s) + s)^(1/t) - 1, t -> ?].
>
> I dont see whats going wrong. Does limit only compute numerical
> expression?
>
> Thanks for your help
>
> Frank
>
|
|
|
|
|