Home > Archive > Unix Programming > March 2006 > shell + filter (eng)
You are viewing an archived Text-only version of the thread.
To view this thread in it's original format and/or if you want to reply to
this thread please [click here]
| Author |
shell + filter (eng)
|
|
| Laurent Deniau 2006-03-30, 7:02 pm |
| (sorry for the previous french version, wrong newsgroup)
I have a string containing a list of tokens separated by spaces (or by
\n after a sed if required) and I would like to remove the last
character of each token if and only if it is a '_' (underscore). Any
Idee? Thanks.
a+, ld.
| |
| elrado@abv.bg 2006-03-30, 7:02 pm |
| echo asdf_asdf asdf_ _asdf asdf asdf__ __ | sed
's/\([[:alnum:]_]\)_[[:>:]]/\1/g'
this one will substitute every occurence of x_ with x, where x is any
alnum character plus _.
[[:>:]] stands for non word boundary. man 7 re_format.
| |
| Laurent Deniau 2006-03-30, 7:02 pm |
| elrado@abv.bg wrote:
> echo asdf_asdf asdf_ _asdf asdf asdf__ __ | sed
> 's/\([[:alnum:]_]\)_[[:>:]]/\1/g'
> this one will substitute every occurence of x_ with x, where x is any
> alnum character plus _.
Thanks.
> [[:>:]] stands for non word boundary. man 7 re_format.
This is what I was missing (not in my man 7 regex = re_format).
a+, ld.
|
|
|
|
|