Scheme - Re: Silly question - Why doesn't a non-procedure expr evaluate to itself in a procedu

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Re: Silly question - Why doesn't a non-procedure expr evaluate to itself in a procedu

Adrian

2007-06-15, 7:13 pm

On Jun 15, 11:02 pm, Nils M Holm <before-2007-07...@online.de> wrote:

> And while we are at it, we could also remove the position
> dependency of the aruments of - and assert
>
> (- x y) = (- y x)
>
> I guess there are some limits to regularity.

With that example, you are removing meaning by doing away with the
ordering of parameters.

With my question, you would be expanding the scope of syntactically
valid programs.

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