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Author Re: Silly question - Why doesn't a non-procedure expr evaluate to itself in a procedu
Adrian

2007-06-15, 7:13 pm

> For identity there is (lambda (x) x) and for sequencing expressions,
> there is BEGIN, so you do not have to invent anything new.

Thanks Nils, I guess the answer then is that it would be syntactically
superfluous?



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