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| Link Skywalker 14 2004-03-28, 10:00 pm |
| I copied this directly from the book "C: step by step" published in
1989, it refuses to compile. Anybody see what's wrong with it? Much
appreciated.
#include <stdio.h>
main()
{
float weight, value;
char beep;
beep = '\007';
printf("Are you worth your weight in gold?\n");
printf("Please enter your weight in punds, ");
printf ("and we'll see.\n");
scanf("%f", $weight);
value = 400.0 * weight * 14.5833;
printf("%cYour weight in gold is worth $%.2f%c.\n",beep,value,beep);
printf("You are easily worth that! If gold prices drop, ");
printf("Eat more\nto maintain your value.\n");
}
This is the error message I get:
c:\program files\miracle c\weight_in_gold.c: line 10: Parse Error,
expecting `')'' or `',''
'scanf("%f", $weight)'
aborting compile
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| Arthur J. O'Dwyer 2004-03-28, 10:00 pm |
|
On Sun, 27 Mar 2004, Link Skywalker 14 wrote:
>
> I copied this directly from the book "C: step by step" published in
> 1989, it refuses to compile. Anybody see what's wrong with it? Much
> appreciated.
>
> #include <stdio.h>
> main()
int main(void)
> {
> float weight, value;
> char beep;
> beep = '\007';
> printf("Are you worth your weight in gold?\n");
> printf("Please enter your weight in punds, ");
Copied it directly, huh?
> printf ("and we'll see.\n");
> scanf("%f", $weight);
Nope -- $ is not &. Try a more direct copy next time.
> value = 400.0 * weight * 14.5833;
> printf("%cYour weight in gold is worth $%.2f%c.\n",beep,value,beep);
> printf("You are easily worth that! If gold prices drop, ");
> printf("Eat more\nto maintain your value.\n");
return 0;
> }
-Arthur
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| Martin Ambuhl 2004-03-28, 10:00 pm |
| Link Skywalker 14 wrote:
> I copied this directly from the book "C: step by step" published in
> 1989, it refuses to compile. Anybody see what's wrong with it? Much
> appreciated.
2c2
< main()
---
> int main(void)
10c10
< scanf("%f", $weight);
---
> scanf("%f", &weight);
16c16
<
---
> return 0;
> #include <stdio.h>
> main()
> {
> float weight, value;
> char beep;
> beep = '\007';
> printf("Are you worth your weight in gold?\n");
> printf("Please enter your weight in punds, ");
> printf ("and we'll see.\n");
> scanf("%f", $weight);
> value = 400.0 * weight * 14.5833;
> printf("%cYour weight in gold is worth $%.2f%c.\n",beep,value,beep);
> printf("You are easily worth that! If gold prices drop, ");
> printf("Eat more\nto maintain your value.\n");
>
> }
>
>
> This is the error message I get:
>
> c:\program files\miracle c\weight_in_gold.c: line 10: Parse Error,
> expecting `')'' or `',''
> 'scanf("%f", $weight)'
^^
notice!
> aborting compile
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| Materialised 2004-03-28, 10:00 pm |
| Link Skywalker 14 wrote:
> I copied this directly from the book "C: step by step" published in
> 1989, it refuses to compile. Anybody see what's wrong with it? Much
> appreciated.
>
> #include <stdio.h>
> main()
> {
> float weight, value;
> char beep;
> beep = '\007';
> printf("Are you worth your weight in gold?\n");
> printf("Please enter your weight in punds, ");
> printf ("and we'll see.\n");
> scanf("%f", $weight);
<snip>
scanf("%f", &weight);
-=-=-
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| |
| Christopher Benson-Manica 2004-03-29, 11:30 am |
| Link Skywalker 14 <linkskywalker14@yahoo.com> spoke thus:
> char beep;
> beep = '\007';
> printf("%cYour weight in gold is worth $%.2f%c.\n",beep,value,beep);
Non-portable; use the standard \a (BEL) escape sequence in the printf
instead to get the "beep".
--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cyberspace.org | don't, I need to know. Flames welcome.
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