AWK - match command ?

Author

match command ?

Stu

2005-05-03, 8:55 pm

Can somebody point me in the right direction.

I am trying to create an awk statement to see if the value of VAR (22)
is in the variable VARLIST. In my example below it is there but by
found flag is not printing 1, which I think it should be.

What do I need to do to get this to work. A working example would be
very much appreciated.

Thanks in advance to anybody who answers this post

#!/bin/ksh

VAR=22
VARLIST="1 22 45"

let found=0
eval `echo ${VAR} | nawk ' (index ($0, pattern))print "found=1"} '
pattern="$VARLIST" `

echo "|$found|"

Ed Morton

2005-05-03, 8:55 pm

Stu wrote:
> Can somebody point me in the right direction.
>
> I am trying to create an awk statement to see if the value of VAR (22)
> is in the variable VARLIST. In my example below it is there but by
> found flag is not printing 1, which I think it should be.
<snip>
>
> #!/bin/ksh
>
>
> VAR=22
> VARLIST="1 22 45"
>
>
> let found=0
> eval `echo ${VAR} | nawk ' (index ($0, pattern))print "found=1"} '
> pattern="$VARLIST" `
>
> echo "|$found|"
>

You've got your logic backward. This:

index ($0, pattern)

will find the first occurence of pattern (i.e. "1 22 45") in $0 (i.e.
"22"). You want to do the reverse:

index (pattern, $0)

There's better ways to do that in awk but there's absolutely no need for
awk to do that in ksh (hint - use a "case"). If you want more awk help,
follow up here. FOr a ksh solution post to comp.unix.shell.

Ed.

Bob Harris

2005-05-03, 8:55 pm

In article <1115153244.304041.224840@f14g2000cwb.googlegroups.com>,
"Stu" <beefstu350@hotmail.com> wrote:

> Can somebody point me in the right direction.
>
> I am trying to create an awk statement to see if the value of VAR (22)
> is in the variable VARLIST. In my example below it is there but by
> found flag is not printing 1, which I think it should be.
>
>
> What do I need to do to get this to work. A working example would be
> very much appreciated.
>
> Thanks in advance to anybody who answers this post
>
> #!/bin/ksh
>
>
> VAR=22
> VARLIST="1 22 45"
>
>
> let found=0
> eval `echo ${VAR} | nawk ' (index ($0, pattern))print "found=1"} '
> pattern="$VARLIST" `
>
> echo "|$found|"

if [[ $VARLIST = $VAR\ * || \
$VARLIST = *\ $VAR\ * || \
$VARLIST = *\ $VAR ]]; then
echo "found"
fi

Or make sure VARLIST always has a token before and after each value

VARLIST=":1:22:45:"
if [[ "$VARLIST" = *:$VAR:* ]]; then
echo "found"
fi

OK, now beat me up for not giving an awk answer :-)

Bob Harris

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