AWK - awk /%/

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awk /%/

frank

2005-01-27, 8:55 pm

does anyone know what

awk /%/ does ( its true meaning )

eg

#df -k | awk /%/ | sort +5

what is the awk /%/ doing here and could it simply put like this

#df -k | sort +5
The object is to sort the last column alphabetically

Frank

Ed Morton

2005-01-27, 8:55 pm

frank wrote:
> does anyone know what
>
> awk /%/ does ( its true meaning )

It selects input records that contain a "%" sign.

> eg
>
> #df -k | awk /%/ | sort +5
>
> what is the awk /%/ doing here

Getting rid of any output from df -k that doesn't contan a %.

and could it simply put like this
>
> #df -k | sort +5
> The object is to sort the last column alphabetically

Yes if every line df -k output contains a %, no otheriwse.

Ed.

>
> Frank
>

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