AWK - getting a block of data help

Author

getting a block of data help

Doug VT

2004-11-22, 3:56 am

Hello all,

I am pretty good at lsh and sed, but awk eludes me atm, so am looking
for some help. I have a file with the following format:

(bunch of lines I don't care about)
*
* xxxxxxx SUMMARY:
*
(a few more lines that vary)
****************************************
*******

Not sure which would be easier, but basically I want to search for the
SUMMARY statement and then print that line up to the
******************** line

OR if that is not easily done then, print the SUMMARY line and the
next 12 lines following it.

Any help would be appreciated.

Thanks,

Doug

Joe Farish

2004-11-22, 3:56 am

> OR if that is not easily done then, print the SUMMARY line and the
> next 12 lines following it.

I know someone has already posted the prefered solution but here is my
attempt at the alternative solution:

awk '/SUMMARY:/{a = 1}{if (a == 1) {b = b + 1}}{if ((b >= 1) && (b <
14)) {print}}' INPUT

How it works:

When AWK finds SUMMARY: a is assigned the value of 1.

When a = 1, the value of b is increased by one everytime a new line is
read.

As long as B is between 0 and 14 the line will be printed.

Janis Papanagnou

2004-11-22, 3:56 am

Doug VT wrote:
> Hello all,
>
> I am pretty good at lsh and sed, but awk eludes me atm, so am looking
> for some help. I have a file with the following format:
>
> (bunch of lines I don't care about)
> *
> * xxxxxxx SUMMARY:
> *
> (a few more lines that vary)
> ****************************************
*******
>
> Not sure which would be easier, but basically I want to search for the
> SUMMARY statement and then print that line up to the
> ******************** line

awk '/SUMMARY:/,/^\*\*+$/'

i.e. up to a line containing only stars and at least two of it (if
you don't want to count and escape each star).

> OR if that is not easily done then, print the SUMMARY line and the
> next 12 lines following it.
>
> Any help would be appreciated.
>
> Thanks,
>
> Doug

Janis

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