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Class resources failing
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| Daniel Sjoblom 2004-03-30, 9:50 am |
| I'm using SomeClass.class.getResource("somefile").getPath() to read in
some file from a local harddrive. It works fine if there is no
whitespace in the path name, but fails miserably if there is. All the
whitespace is replaced by %20. Now, I know how to fix this, but then my
app will fail if someone has the characters %20 in their path. Should I
perhaps use something else? (This is on windows btw. I haven't tested it
on linux yet, since I haven't downloaded a VM yet (just installed
Mandrake Linux this w end.))
--
Daniel Sjöblom
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| Andrew Thompson 2004-03-30, 11:49 am |
| On Tue, 30 Mar 2004 07:28:31 +0300, Daniel Sjoblom wrote:
> I'm using SomeClass.class.getResource("somefile").getPath() to read in
> some file from a local harddrive.
Stick with the URL..
You can either
Class.getResourceAsStream(String)
or.. URL.openStream()
That way, you can access
1) files on file system
2) files on the net
3) files inside zip/jar archives
If you find you have trouble with
some URL's still, look into URI's,
they can even handle file names
containing the '#' character, which
URL will interpret as an URL 'fragment' -
a link inside a document.
HTH
--
Andrew Thompson
http://www.PhySci.org/ Open-source software suite
http://www.PhySci.org/codes/ Web & IT Help
http://www.1point1C.org/ Science & Technology
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| Daniel Sjöblom 2004-03-31, 2:41 pm |
| Andrew Thompson wrote:
> On Tue, 30 Mar 2004 07:28:31 +0300, Daniel Sjoblom wrote:
>
>
>
>
> Stick with the URL..
>
> You can either
> Class.getResourceAsStream(String)
> or.. URL.openStream()
>
> That way, you can access
> 1) files on file system
> 2) files on the net
> 3) files inside zip/jar archives
This works. Thanks.
--
Daniel Sjöblom
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