PHP Language - Leaning php

Author

Leaning php

Jimbo

2006-05-10, 6:58 pm

I purchased a "Learn PHP" book and am trying to teach myself. Here is a
function from the book which is not working.

Could someone tell me what I am doing incorrectly.

Here is the error message:
Parse error: syntax error, unexpected '=' in
/home/dandgra/public_html/phptest/chp7.php on line 18

Here is the code:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>Chp 7</title>
</head>

<body>
<h1>Arrays Chapter 7 </h1>
<?php

// this is not working
function addNums ( ) {
$ret = "<table border=\"1\">";
for ( $x=0; $x<func_num_arg(); $x++){
$arg = func_get_arg($x);
$result += $arg;
$ret . = "<tr><td>number ".($x+1).":</td><td>$arg</td></tr>";
}
$ret .= "<tr><td>result: </td><td>$result</td></tr>";
$ret .="</table>";
return $ret;
}
print addNums (3, 4, 6, 99);

?>
</body>
</html>

Dave Kelly

2006-05-10, 6:58 pm

Jimbo wrote:
> I purchased a "Learn PHP" book and am trying to teach myself. Here is a
> function from the book which is not working.
>
> Could someone tell me what I am doing incorrectly.
>
> Here is the error message:
> Parse error: syntax error, unexpected '=' in
> /home/dandgra/public_html/phptest/chp7.php on line 18
>
> Here is the code:
>
> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
> "http://www.w3.org/TR/html4/loose.dtd">
> <html>
> <head>
> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
> <title>Chp 7</title>
> </head>
>
> <body>
> <h1>Arrays Chapter 7 </h1>
> <?php
>
> // this is not working
> function addNums ( ) {
> $ret = "<table border=\"1\">";
> for ( $x=0; $x<func_num_arg(); $x++){
> $arg = func_get_arg($x);
> $result += $arg;
> $ret . = "<tr><td>number
> ".($x+1).":</td><td>$arg</td></tr>";
> }
> $ret .= "<tr><td>result: </td><td>$result</td></tr>";
> $ret .="</table>";
> return $ret;
> }
> print addNums (3, 4, 6, 99);
>
>
> ?>
> </body>
> </html>

Being a new coder myself, I don't have an answer. But I do have a question.

$ret = "<table border=\"1\">";
$ret . = "<tr><td>number>".($x+1).":</td><td>$arg</td></tr>";
$ret .= "<tr><td>result: </td><td>$result</td></tr>";

Are the first 7 charecter of the 3 lines above suppose to be the same?
Or correct as is?

Cédric Olmanst

2006-05-10, 6:58 pm

(sorry for my English)

Jimbo a écrit :
> function addNums ( ) {
> $ret = "<table border=\"1\">";
> for ( $x=0; $x<func_num_arg(); $x++){
> $arg = func_get_arg($x);
> $result += $arg;

It's the first line I see $result. Where does it come from ?

> $ret . = "<tr><td>number ".($x+1).":</td><td>$arg</td></tr>";
> }
> $ret .= "<tr><td>result: </td><td>$result</td></tr>";
> $ret .="</table>";
> return $ret;
> }
> print addNums (3, 4, 6, 99);

Rik

2006-05-10, 6:58 pm

Jimbo wrote:
> $ret . = "<tr><td>number ".($x+1).":</td><td>$arg</td></tr>";

Change this to
$ret .= "<tr><td>number ".($x+1).":</td><td>$arg</td></tr>";

'.=' is an operator, '. =' isn't,

Your code would translate like:
$ret combined with '=', which isn't a function, a variable or an allowed
constantname.

http://www.php.net/manual/en/language.operators.php

Grtz,
--
Rik Wasmus

Jimbo

2006-05-11, 6:58 pm

Thanks for the help and the php manual link.

Rik wrote:
> Jimbo wrote:
>
>
> Change this to
> $ret .= "<tr><td>number ".($x+1).":</td><td>$arg</td></tr>";
>
> '.=' is an operator, '. =' isn't,
>
> Your code would translate like:
> $ret combined with '=', which isn't a function, a variable or an allowed
> constantname.
>
> http://www.php.net/manual/en/language.operators.php
>
> Grtz,

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