PHP Language - Daft ereg_replace() question.....

Author

Daft ereg_replace() question.....

Bonge Boo!

2004-05-12, 7:21 pm

I thought this would be easy, but have wasted the best part of 2 hrs trying
to make it work

I have a string:

$string = "!!shocking.jpg";

I want to strip of the !! and replace with a single underscore. I'd like to
do that at any position in the string.

I know that ereg_repalce or preg_replace will do this, but I can't make it
work. If I use the following GREP syntax in Bbedit (Mac text editing
programming) it would work

preg_replace( '[\!]+' , '' , $string );

So I'm guessing that preg_ and ereg_ escape characters must be different? Or
is there something special about ! ?

Janwillem Borleffs

2004-05-12, 7:21 pm

Bonge Boo! wrote:
> So I'm guessing that preg_ and ereg_ escape characters must be
> different? Or is there something special about ! ?

You are thinking to difficult here, the following should be sufficient:

$bla = '!!en!!dat!!';
print preg_replace("/!+/", "_", $bla);

JW

Bonge Boo!

2004-05-14, 6:30 am

On 9/5/04 1:22, in article 409d79e0$0$65933$a344fe98@news.wanadoo.nl,
"Janwillem Borleffs" <jw@jwscripts.com> wrote:

>
> You are thinking to difficult here, the following should be sufficient:
>
> $bla = '!!en!!dat!!';
> print preg_replace("/!+/", "_", $bla);

Damn. I'm an idiot. I had:

preg_replace( $preg_replace , " " , $photos_uploaded_clean );

Thinking that would then replace the value of $photos_uploaded_clean with
the preg_replace function, and hence would be able to:

print $photos_uploaded_clean; and see the result.

But I guess that would only happen is I had:

$photos_uploaded_clean = preg_replace( $preg_replace , " " ,
$photos_uploaded_clean );

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