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Home > Archive > PHP on Windows > October 2007 > Re: [PHP-WIN] fopen on windows shared, error: failed to open stream









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Author Re: [PHP-WIN] fopen on windows shared, error: failed to open stream
Niel Archer

2007-10-28, 8:01 am

> I have this error when ever i try to save an xml file over a windows shared
> folder
>
> *Warning*:
> fopen(\\192.168.10. 2\businesscard\XML\afbf7d1fb318054a5ba3e
9d4cca0af.xml) [
> function.fopen]: failed to open stream: Invalid argument in *
> E:\\businesscard\create.php* on line *663*
>
> my code:
> $createXML =
> fopen("\\\\192.168.10.2\businesscard\XML\".$xml_uniq_session.".xml", "w");
> $_xml ="<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?>\r\n";
> ....
> fwrite($createXML, $_xml, strlen($createXML));
> fclose($createXML);
>
> What could be the problem?


Your path is probably invalid as backslashes are escapes inside double
quotes. So the single backslashes act as escapes on the following
character, which results in no separation between directories.
Workarounds include:
Use forward slashes for paths inside double quotes,
fopen("////192.168.10.2/businesscard/XML/" . $xml_uniq_session . ".xml", "w");
escape the backslashes themselves
fopen("\\\\\\\\192.168.10.2\\businesscard\\XML\\".$xml_uniq_session.".xml",
"w");
or single quotes
fopen('\\\\192.168.10.2\businesscard\XML' . $xml_uniq_session . '.xml', "w");

--
Niel Archer
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