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Author RE: [PHP-DB] width& height
Xuepeng Li

2007-03-31, 6:57 pm

<?php echo "<img src='/album/img/".$photoFileName[2]." width="90"
height="70" border='0' / >"; ?>

Should be:

<?php
echo "<img src='/album/img/" . $photoFileName[2] . " width=\"90\"
height=\"70\" border='0' / >";
?>

Or

<?php
echo "<img src='/album/img/" . $photoFileName[2] . " width='90'
height='70' border='0' / >";
?>

Or

<?php
echo '<img src="/album/img/' . $photoFileName[2] . ' width="90"
height="70" border="0" / >';
?>

And the third one is the best.



-----Original Message-----
From: elk dolk [mailto:elkdolk@yahoo.com]
Sent: Friday, March 30, 2007 7:32 PM
To: php-db@lists.php.net
Subject: [PHP-DB] width& height

it might be a stupid question but I think it would be the last one!
I am trying to define the height and width of picture in the following line:

"<img src='/album/img/".$photoFileName[2]." / >"; ?></td>

when I put it like this:

<table width="50%" border="0" cellspacing="3" cellpadding="0">
<tr>
<td width="90" height="70"><?php echo "<img
src='/album/img/".$photoFileName[2]." width="90" height="70" border='0' /
>"; ?></td>


</tr>
<tr>
<td width="90" height="70"> </td>
<td width="90" height="70"> </td>
</tr>
</table>
<p> </p>
<p>

I have this error:
PHP Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';' in
C:\Inetpub\wwwroot\album\2dimArray2.php on line 44

please comment!

---------------------------------
Bored stiff? Loosen up...
Download and play hundreds of games for free on Yahoo! Games.
JM Guillermin

2007-03-31, 6:57 pm

Try this one :

<table width="50%" border="0" cellspacing="3" cellpadding="0">
<tr>
<td width="90" height="70">
<img src="/album/img/<?= $photoFileName[2] ?>" width="90" height="70"
border="0" / >
</td>
</tr>
</table>

Or :

<table width="50%" border="0" cellspacing="3" cellpadding="0">
<tr>
<td width="90" height="70">
<img src="/album/img/<?php echo $photoFileName[2] ?>" width="90"
height="70" border="0" / >
</td>
</tr>
</table>


the second if your php.ini don't allow short tag usage.

jm



----- Original Message -----
From: "Xuepeng Li" <lucus.li@alibaba-inc.com>
To: "'elk dolk'" <elkdolk@yahoo.com>; <php-db@lists.php.net>
Sent: Saturday, March 31, 2007 6:40 PM
Subject: RE: [PHP-DB] width& height


> <?php echo "<img src='/album/img/".$photoFileName[2]." width="90"
> height="70" border='0' / >"; ?>
>
> Should be:
>
> <?php
> echo "<img src='/album/img/" . $photoFileName[2] . " width=\"90\"
> height=\"70\" border='0' / >";
> ?>
>
> Or
>
> <?php
> echo "<img src='/album/img/" . $photoFileName[2] . " width='90'
> height='70' border='0' / >";
> ?>
>
> Or
>
> <?php
> echo '<img src="/album/img/' . $photoFileName[2] . ' width="90"
> height="70" border="0" / >';
> ?>
>
> And the third one is the best.
>
>
>
> -----Original Message-----
> From: elk dolk [mailto:elkdolk@yahoo.com]
> Sent: Friday, March 30, 2007 7:32 PM
> To: php-db@lists.php.net
> Subject: [PHP-DB] width& height
>
> it might be a stupid question but I think it would be the last one!
> I am trying to define the height and width of picture in the following
> line:
>
> "<img src='/album/img/".$photoFileName[2]." / >"; ?></td>
>
> when I put it like this:
>
> <table width="50%" border="0" cellspacing="3" cellpadding="0">
> <tr>
> <td width="90" height="70"><?php echo "<img
> src='/album/img/".$photoFileName[2]." width="90" height="70" border='0' /
>
> </tr>
> <tr>
> <td width="90" height="70"> </td>
> <td width="90" height="70"> </td>
> </tr>
> </table>
> <p> </p>
> <p>
>
> I have this error:
> PHP Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';'
> in
> C:\Inetpub\wwwroot\album\2dimArray2.php on line 44
>
> please comment!
>
> ---------------------------------
> Bored stiff? Loosen up...
> Download and play hundreds of games for free on Yahoo! Games.
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

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