| Bastien Koert 2007-03-30, 6:57 pm |
| you need to escape double quotes in an echo if you use double quotes as the
wrapper.
bastien
>From: elk dolk <elkdolk@yahoo.com>
>To: "php-db@lists.php.net" <php-db@lists.php.net>
>Subject: [PHP-DB] width& height
>Date: Fri, 30 Mar 2007 04:31:52 -0700 (PDT)
>
>it might be a stupid question but I think it would be the last one!
>I am trying to define the height and width of picture in the following
>line:
>
>"<img src='/album/img/".$photoFileName[2]." / >"; ?></td>
>
>when I put it like this:
>
><table width="50%" border="0" cellspacing="3" cellpadding="0">
> <tr>
> <td width="90" height="70"><?php echo "<img
>src='/album/img/".$photoFileName[2]." width="90" height="70" border='0' /
>
> </tr>
> <tr>
> <td width="90" height="70"> </td>
> <td width="90" height="70"> </td>
> </tr>
></table>
><p> </p>
><p>
>
>I have this error:
>PHP Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';'
>in C:\Inetpub\wwwroot\album\2dimArray2.php on line 44
>
>please comment!
>
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