| Alexander 2007-01-27, 9:58 pm |
| I fixed my code and it shows up fine now. It says it supposedly enters the
data when I input the fields but when I check the MySQL database, the info
isn't there.
Here's the fixed code if you wish to test it:
<html>
<body>
<?php
function add_to_table( $picture, $thumbnail ) {
$picture = mysql_real_escape_string($picture);
$thumbnail = mysql_real_escape_string($thumbnail);
$user = "user";
$pass = "password";
$database = "mydata";
$link = mysql_connect("localhost", $user, $pass);
if(!$link) {
echo 'Error in linking';
}
$db = mysql_select_db($database, $link);
$insert = 'INSERT INTO domains ( picture, thumbnail ) values(
$picture, $thumbnail )';
$indata = mysql_query( $insert, $link );
}
function write_form() {
echo "<form method='post' action='{$_SERVER['PHP_SELF']}'>";
echo "<p>Enter url of large picture: <input type='text'
name='picture' />";
echo "<p>Enter url of thumbnail: <input type='text'
name='thumbnail' />";
echo "<p><input type='submit' value='Add to Database' />";
echo "</form>";
}
if ( !empty( $_REQUEST['picture'] ) && !empty(
$_REQUEST['thumbnail'] ) ) {
$input = add_to_table( $_REQUEST['picture'],
$_REQUEST['thumbnail'] );
if(!input) {
echo 'Error\!';
}
else {
echo 'Data enter successfully\!';
$idreturn = mysql_insert_id($input);
echo 'Image inserted to ID ' . $idreturn;
}
}
else {
write_form();
}
?>
</body>
</html>
|