PHP DB - Scriptproblem

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Author

Scriptproblem

Ruprecht Helms

2006-01-24, 6:56 pm

Hi,

how can I display the stored data of an user as value in a formfield.
Actualy the formfield "vorname" shows no entry and the formfield "name"
shows .$row->Name.

What is the correct syntax in this case.

Regards,
Ruprecht

<?
mysql_connect("localhost",<user>,<password> );
$result=mysql_db_query("salzert","SELECT * FROM Benutzer WHERE ID=$id");
echo '<input type="text" name=id value="';
echo $id;
echo '">';
echo "<tr>";
echo " <td>Vorname</td>";
echo '<td><input type="text" name="vorname" value="';
echo $row->Vorname;
echo '"></td>';
echo "</tr>";
echo "<tr>";
echo " <td>Name</td>";
echo '<td><input type="text" name="name" value=".$row->Name."></td>';
echo "</tr>";
....
?>

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