| RaJeSh VeNkAtA 2006-01-14, 6:56 pm |
| u can have the query as
$query = " select * from $table where nameId = 31 " ;
$result = mysql_query ( $query ) ;
$i = 0 ;
while ( $row = mysql_fetch_array( $result , MYSQL_NUM ) )
{
$array[$i][0] = $row[0] ;
$array[$i][1] = $row[1] ;
$array[$i][2] = $row[2] ;
$i++
}
// now $array has ur required names :-)
rajesh
On Sat, 14 Jan 2006, Sjef Janssen wrote:
> Hi there,
> I have a table that keeps names for different language codes.
> In a short example:
> nameId name languageCode
> 31 House EN
> 31 Wohnung DE
> 32 Piece En
> 32 Stuck De
> 33 Car EN
> 33 PKW DE
>
> What I would like is to have a query that returns for example:
> nameId = 31
> Names = House - Wohnung
>
> Maybe I can even have a result that consists of an array with nameIds and
> Names.
> Or should I fire a bunch of queries after each other to have this result?
>
> I use mysql and php 4.3.8
>
> Tnxs!!
>
>
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