| Darryl 2004-12-27, 3:55 pm |
| From what I see, the code is fine, you just haven't finished it.
mysql_query("INSERT INTO totalinfo (Username,Password) VALUES
('$loginusername','$loginpassword'),$dbh
")or die (mysql_error());
}
Give that a bash
-----Original Message-----
From: John Hicks [mailto:johnlist@gulfbridge.net]
Sent: Monday, December 27, 2004 4:40 PM
To: amol patil
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] check out this , if block is not executing
.............
amol patil wrote:
>hallo ,
>
>entered information still not shown in table of database
>
>is below code is right ?
>form name and type values are 'submit' . then
>
>what is wrong with this code,
>
><?php
>
>if(isset($_POST['submit']))
>{
>
> $dbh=mysql_connect ("localhost", "root") or die ('I cannot connect to
>the database because: ' . mysql_error());
>mysql_select_db ("dollar1_allinfo");
>
> mysql_query("INSERT INTO totalinfo (Username,Password) VALUES
>('$loginusername','$loginpassword')")or die (mysql_error());
>}
>?>
>
>
Are you getting any error messages when you click on 'submit'? (Check
your php log.)
Include an 'else' in your if statement (along with a debug message) so
you can see if the 'submit' is detected.
-John
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