| Juan Stiller 2004-11-01, 3:55 pm |
| Thanks for the response,
Now its fixed, and this is the output for the code:
&Id=28&Apellido= ff&Nombre=asdfsdf&Dni=fsdf&Telefono=ff&Dia=1&Mes=12&Ano=2004&Hora=9&Minutos=50&Abogado=Dra.
Claudia I.
Gorno&Nombre=asdfsdf&Asunto=asdfsd&Donde=Guia Barrial
Palermo&Id=26&Apellido=Sarasa&Nombre=Exequiel&Dni=23453425&Telefono=423452345&Dia=2&Mes=2&Ano=2005&Hora=12&Minutos=30&Abogado=Dra.
Claudia I.
Gorno&Nombre=Exequiel&Asunto=3452345&Donde=Guia
Barrial
Palermo&Id=27&Apellido=Zarlanga&Nombre=Washington&Dni=4234235&Telefono=1234234&Dia=10&Mes=2&Ano=2004&Hora=18&Minutos=15&Abogado=Dra.
Claudia I.
Gorno&Nombre=Washington&Asunto=fsdf&Donde=RadioDiez
- Sensacion Termica
But this is not showing the result as:
&Id1=28&Apellido1=whatever.....
So im having the same problem i had before? the
variables are been overwritten over and over again.
What am i doing wrong?
--- "Demigod at SD41.net" <demigod@sd41.net>
escribió:
> Here's your hint:
> The variable you are passing to mysql_num_rows is
> undefined. If what
> you want is the number of rows returned by
> mysql_query, then you need to
> pass $result1 to mysql_num_rows instead. Also note
> that you again use
> the undefined $qr as the argument for
> mysql_fetch_array two lines later.
>
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