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| Author |
Control Structure Question
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| Dave Adams 2005-07-24, 8:29 pm |
| The following code looks too rigid, how can I achieve the same result
using one of the control structure (foreach, for, etc)?
#!/usr/bin/perl -w
use strict;
use Date::Calc qw(:all);
my @today =3D Today();
my $year_now =3D $today[0];
my $month_now =3D $today[1];
my $day_now =3D $today[2];
print ($year_now);
print ("=3D=3D=3D\n");
print ($month_now);
print ("=3D=3D=3D\n");
print ($day_now);
print ("=3D=3D=3D\n");
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| Jeff 'japhy' Pinyan 2005-07-24, 8:29 pm |
| On Jul 22, Dave Adams said:
> The following code looks too rigid, how can I achieve the same result
> using one of the control structure (foreach, for, etc)?
> my @today = Today();
> my $year_now = $today[0];
> my $month_now = $today[1];
> my $day_now = $today[2];
Well, first of all, that could just be:
my ($year_now, $month_now, $day_now) = Today();
> print ($year_now);
> print ("===\n");
> print ($month_now);
> print ("===\n");
> print ($day_now);
> print ("===\n");
And those could be:
print "$_===\n" for $year_now, $month_now, $day_now;
And if Today() only returns those three values, you could do:
print "$_===\n" for Today();
If Today() returns more than three values, then you could do:
print "$_===\n" for (Today())[0..2];
--
Jeff "japhy" Pinyan % How can we ever be the sold short or
RPI Acacia Brother #734 % the cheated, we who for every service
http://japhy.perlmonk.org/ % have long ago been overpaid?
http://www.perlmonks.org/ % -- Meister Eckhart
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