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Author Re[2]: apache log parsing
John

2005-03-31, 3:56 pm

=0D=0AFrom: John Doe <security.department@tele2.ch>
To: beginners@perl.org
Date: Thursday, March 31, 2005, 2:24:24 PM
Subject: apache log parsing



Thursday, March 31, 2005, 2:24:24 PM, you wrote:

> Am Donnerstag, 31. M=E4rz 2005 11.08 schrieb John:
[color=darkred]
> Always use "use strict; use warnings" in your code - it gives you very go=

od
> hints:


> use strict;=20
> use warnings;
> my $datetime=3D"DD/MM/YYYY:HH:MM:SS";
> @fields=3Dsplit(/[/:]/, $datetime);


> # This prints out:
> Global symbol "@fields" requires explicit package name at - line 3.
> Unmatched [ in regex; marked by <-- HERE in m/[ <-- HERE / at - line 3.


> Here is the modified code:


> use strict; use warnings;
> my $datetime=3D"DD/MM/YYYY:HH:MM:SS";
> my @fields1=3Dsplit(/[\/:]/, $datetime); # [1]
> my @fields2=3Dsplit(m,[/:],, $datetime); # [2]
> print join ", ", @fields1;
> print "\n";
> print join ", ", @fields2;


> # This prints out:
> DD, MM, YYYY, HH, MM, SS
> DD, MM, YYYY, HH, MM, SS


> To avoid perl interpreting a "/" searched for with the end of the regex, =

you
> either have to=20
> [1] escape "/" with " \"
> or=20
> [2] use another "delimiter" (don't know the english term at the moment) f=

or
> the match regex - in this case, "m,," instead of "//", explicitly indicat=

ing
> the match with an "m".


> see perldoc perlre


> joe




Yeah, it worked. Thanks a lot.

I found the a module Apache::Regexp can parse apache logs
but i am afraid it cannot output statistics just does what
i am trying to do subsrt the datetime, hosts, etc.


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