PERL Beginners - CGI changes

Author

CGI changes

Kamalraj Singh Madhan

2005-10-20, 4:00 am

Hi Guys,
I have a cgi which automates the task of zipping up a complete
directory and its sub directories:

echo "Content-type: text/html"
echo ""
echo "<html><head></head>"
echo "<body>"
echo "Building tar file... "
echo "<tt>"
cd /var/www/html/
for type in test;
do
filen=3D${type//\//-}
echo " Building ${filen}.tgz "
tar cvfz files/${filen}.tgz --sparse ${type}
echo " "
echo "See <a href=3D'/files/${filen}.tgz'>/files/${filen}.tgz</a>. "
done;
echo "</tt> "
echo "Done."
echo "</body></html>"=20

Now I want to add the current date to the name of the zipped up file
i.e. to the variable named 'filen' in the above script...=20

Is there any date function in shell scripting which can solve this
problem? Kindly suggest.=20

Regards
Kamal =20

Xavier Noria

2005-10-20, 4:00 am

On Oct 20, 2005, at 9:24, Kamalraj Singh Madhan, Noida wrote:

> Now I want to add the current date to the name of the zipped up file
> i.e. to the variable named 'filen' in the above script...
>
> Is there any date function in shell scripting which can solve this
> problem? Kindly suggest.

Yes, you can do something like this:

today=`date "+%Y-%m-%d"`
backup=~/tmp/backup-${today}.pax

-- fxn

PS: I guess you were asking this in a mailing list about Perl in case
some Perl one-liner could solve it the way date(1) does, but the
idiomatic solution in sh is date(1).

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