PERL Beginners - Inline Edit -- File name

Author

Inline Edit -- File name

RArul@newenergyassoc.com

2004-09-22, 3:57 pm

How will I get the file name when I do an inline edit like this:

perl -i.orig -pe '$_ =3D <filename> $_' filename

How would I get the file name in <filename>?

Thanks,
Rex

RArul@newenergyassoc.com

2004-09-22, 8:58 pm

Well, I did try that with $ARGV[0], but to no avail. Yes, I had posted a =
POC. Here is the true code that would not print the file-name. What am I =
doing wrong?

perl -pe '$_ =3D "$ARGV[0] \t $_"' trace.txt

-----Original Message-----
From: Jose Alves de Castro [mailto:jac@natura.di.uminho.pt]=20
Sent: Wednesday, September 22, 2004 12:40 PM
To: Arul, Rex
Cc: beginners@perl.org
Subject: Re: Inline Edit -- File name

On Wed, 2004-09-22 at 15:24, RArul@newenergyassoc.com wrote:
> How will I get the file name when I do an inline edit like this:
>=20
> perl -i.orig -pe '$_ =3D <filename> $_' filename

That won't compile, but I believe you're posting something like a proof
of concept rather then code...

If I get this correctly, you're looking for the $ARGV variable. Check
out:

perldoc perlvar

> How would I get the file name in <filename>?
>=20
> Thanks,
> Rex
--=20
Jos=E9 Alves de Castro <cog@cpan.org>
http://natura.di.uminho.pt/~jac

RArul@newenergyassoc.com

2004-09-22, 8:58 pm

Thanks for the help.=20

This works: perl -pe '$_ =3D "$ARGV \t $_"' trace.txt =20
This doesn't: perl -pe '$_ =3D "$ARGV[0] \t $_"' trace.txt =20

perldoc perlvar says that $ARGV must be used for command-line processors
and in array-context as @ARGV for running scripts.

Thanks, once again.

-----Original Message-----
From: Arul, Rex=20
Sent: Wednesday, September 22, 2004 1:27 PM
To: 'jac@natura.di.uminho.pt'
Cc: beginners@perl.org
Subject: RE: Inline Edit -- File name

Well, I did try that with $ARGV[0], but to no avail. Yes, I had posted a
POC. Here is the true code that would not print the file-name. What am I
doing wrong?

perl -pe '$_ =3D "$ARGV[0] \t $_"' trace.txt

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