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| Author |
system command via perl script??
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| Eric Haskins 2004-10-04, 8:57 pm |
| Hello,
I currently develop in PHP but I have hit a wall. Is it possible to run
this command and variations of it
killall -USR2 appname
via a web script in perl?? I have an app that runs on my development server
and cant get PHP system() or exec() to work. If it is possible please
direct me to some info on it.
--
Eric Haskins
RackSPEED.Net
WebHosting from $4.99/month
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| Jim Gibson 2004-10-04, 8:57 pm |
| In article <QKj8d.49986$Si.9769@tornado.tampabay.rr.com>, Eric Haskins
<hostmaster_s_p_a_m@rackspeed.net> wrote:
> Hello,
>
> I currently develop in PHP but I have hit a wall. Is it possible to run
> this command and variations of it
>
> killall -USR2 appname
Yes.
>
> via a web script in perl?? I have an app that runs on my development server
> and cant get PHP system() or exec() to work. If it is possible please
> direct me to some info on it.
Perl has a built-in kill function, but it works on PID numbers, not
command names. You can also run the system version of killall with
Perl's system function. If you have access to a perl installation, you
can get more information with
perldoc -f kill
perldoc -f system
A quick search of CPAN (http://search.cpan.org) yields the
Proc::ProcessTable module with its associated Proc::Killall module.
Those might prove useful. If they are installed in your perl, do
perldoc Proc::ProcessTable
perldoc Proc::Killall
If that yields nothing, they are probably not installed. You can
install modules with
perl -MCPAN -e shell
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| Joe Smith 2004-10-05, 8:56 am |
| Eric Haskins wrote:
> Hello,
>
> I currently develop in PHP but I have hit a wall. Is it possible to run
> this command and variations of it
>
> killall -USR2 appname
>
> via a web script in perl?? I have an app that runs on my development server
> and cant get PHP system() or exec() to work.
Are you having problems with system() in general, or just with killall?
If it is the latter, then it is probably because the web server is
running with a different UID than the app is running with.
-Joe
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