simple reg ex matching

Hi,
The value of $_ is 62. In the script below, I just wonder why the default va
riable match the number 6. What I wanted to say is that if the default varia
ble $_ holding the value of 62, if match the number 6, then print Yes match.
 So what is the right way to right.
Thanks

use strict;
use warnings;

my $_ = 62;

if( $_ =~ /6/){
print "Yes match \n";
}else{print "no"};

ok, I found my error, it should be as follows if I want to match number 6:-
my $_ = 62; if( $_ =~ /^6$/){

----- Original Message -----
From: <itshardtogetone@hotmail.com>
To: <beginners@perl.org>
Sent: Wednesday, April 02, 2008 5:07 PM
Subject: simple reg ex matching


Hi,
The value of $_ is 62. In the script below, I just wonder why the default
variable match the number 6. What I wanted to say is that if the default
variable $_ holding the value of 62, if match the number 6, then print Yes
match. So what is the right way to right.
Thanks

use strict;
use warnings;

my $_ = 62;

if( $_ =~ /6/){
print "Yes match \n";
}else{print "no"};

<itshardtogetone@hotmail.com> wrote:

> ok, I found my error, it should be as follows if I want to=20
> match number 6:- my $_ =3D 62; if( $_ =3D~ /^6$/){

Of course you could also just use "if( $_ =3D=3D 6 )".

HTH,
Thomas